volume sebuah kerucut 1.232 cm dan panjang jari alasnya 7 cm luas selimut kerucut

V = 1.232 cm³
R = 7 cm
Ls = ....???

cari t dulu :
V = ¹/₃πR²t
1.232 = ¹/₃ (22/7)(7²)t
       t = 24 cm

cari s dulu :
s = √R² + t² ⇔ s = √7² + 24² = √49 + 576 = √625 = 25 cm

cari Ls :
Ls = πRs ⇔ Ls = (22/7)(7)(25) = 550 cm² ← jawab