Diketahui jari jari kerucut 14 cm, dan tinggi 5 cm, berapa luas selimut kerucut

s= \sqrt{r^{2}+t^{2}}
= \sqrt{(14cm)^{2}+(5cm)^{2}}
= \sqrt{196cm^{2}+25cm^{2}}
= \sqrt{221cm^{2}}
=√221cm

L selimut kerucut=πrs
=22/7(14cm)(√221cm)
=44√221cm

Semoga membantu

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