Matematika

Pertanyaan

tentukan nilai |4-2x|<1

2 Jawaban

  • |4-2x|<1
    Sifat
    -1 < (4-2x)<1
    -1-4< (4-4-2x)<1-4
    -5 < (-2x)<-3

    => -2x <-3
    => x > -3/-2
    => x > 3/2

    => -2x >-5
    => x < -5/-2
    => x < 5/2

    Jadi hp { 3/2


  • |4 - 2x| < 1
    -1 < 4 - 2x < 1
    -1 - 4 < 4 - 2x -4 < 1 - 4
    -5 < -2x < -3
    -5/-2 > -2x/2 > -3/-2
    3/2 < x < 5/2

    HP = {x | 3/2 < x < 5/2, € bilangan real}

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