Matematika

Pertanyaan

|x-2|≤|x+1| tolong di bantu ya kaka"

1 Jawaban

  • |x-2| ≤ |x+1|
    (x-2)²≤ (x+1)²
    (x-2)² - (x+1)²≤ 0
    [(x-2)+ (x+1)]×[(x-2)- (x+1)]≤ 0
    (x-1) ( -3) ≤ 0
    -3x +3 ≤ 0
    -3x ≤ -3
    x≤ 1

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