tentukan suatu segitiga dengan alas (x+2)cmdan luasnya(x²-4)cm² . jika x=3,tentukan urutan segitiga tersebut

a = (x + 2)
Luas = (x² - 4)

Luas = 1/2 × a ×

2× Luas = a × t

2 × (x² - 4) = (x + 2) × t

2× (x + 2) (x - 2) = (x + 2) × t

2× (x + 2) (x - 2)
----------------------- = t
(x + 2)

2×(x - 2) = t

2x - 4 = t

jika x = 3
maka a = x + 2 = 3 + 2 = 5cm
t = 2x - 4 = 2(3) - 4 = 6 - 4 = 2cm

maka luasnya (x²-4) = 3² - 4 = 9 - 4 = 5 cm²

Materi Aljabar

Karena x = 3, maka alas = x + 2 = 3 + 2 = 5 cm
Karena x = 3, maka luas = x² - 4 = 3² - 4 = 5 cm²
L = 1/2 × a × t
5 = 1/2 × 5 × t
t = 2 cm