Diketahui: ²log3=p. ³log5=q. Ditanya: 1.) ³log16. 2.) ⁴log10

2'log 3 = p
Log 3/log 2 = p
P log 2 = log 3
Log 2 = 1/p log 3

3'log 5 = q
Log 5/log 3 = q
Log 5 = q log 3

1) 3'log 16 =
= log 16/log 3
= log 2⁴/log 3
= 4 log 2/log 3
= (4 . 1/p log 3)/log 3
= 4/p

2) 4'log 10 =
= Log 10/log 4
= (Log 2 + log 5)/(log 2²)
= (Log 2 + log 5)/(2 log 2)
= (1/p log 3 + q log 3)/(2 . 1/p log 3)
= (1/p + q)/(2/p)
= (1+pq)/2