Matematika

Pertanyaan

diketahui:g(x)=6-3x+x pangkat 2
nilai 4.g(-2)=

2 Jawaban

  • g(x)= 6-3x+x^2
    g(-2)= 6 - 3(-2) + (-2)^2
    = 6 + 6 + 4
    = 16
    nilai 4.g(-2)= 4. 16 = 64
  • g(x)=6-3x+x^2

    nilai 4.g(-2) = ?

    jadi 4.g(-2) =
    4.{6-3(-2)+(-2)^2} =
    4.{6+6+4} =
    4.{16} =
    64

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