diketahui f(x)= ax + b jika f(3)=-1 dan f (-1)=19 maka nilai a dan b berturut turut adalah?

- f(x) = ax + b
- f(3) = -1
  ⇔ -1 = 3a + b
- f(-1) = 19
  ⇔ 19 = -1a + b
  ⇔ 19 = -a + b

dengan eliminasi =
3a + b = -1
-a + b = 19
_________ _
4a = -20
a = -20/4 = -5

-a + b = 19
-(-5) + b = 19
5 + b = 19
b = 19 - 5
b = 14

Semoga membantu :))

f(x) = ax + b
f(3) = 3a + b = -1 ...(1)
f(-1) = -a + b = 19 ...(2)

eliminasi :
3a + b = -1
-a + b = 19

menjadi
4a = -20
a = -5

subtitusi nilai a ke ...(2)
-a + b = 19
-(-5) + b = 19
b = 19-5 = 14

jdi nilai a= -5 & b= 14