Diameter sebuah kerucut = 20,0 cm, tingginya = 24,0 cm, maka : a. Panjang garis pelukisnya = b. Luas selimutnya = c. Volumenya = d. Luas permukaanya =

Dik : d = 20,0cm -----> r= 10cm
t = 24,0cm
jwb:
a. s² = r² + t²
s² = 10²+ 24,0²
s² = 100+576
s² = 676
s = 26 cm
b. L.selimut = phi×r×s
= 3.14×10×26
= 31.4×26
= 816.4 cm²

c. V.kerucut = 1/3×phi×r²×t
= 1/3×3.14×10×10×24,0
= 1/3×314×24,0
= 1/3×7536
= 2512 cm³

d. L.permukaan = phi × r (r+s)
= 3.14×10 (10+26)
= 31.4 (36)
= 1130.4 cm²
maaf kalau salah,smoga membantu!