Integral 4 dab o (√x-1)² dx
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Integral 4 dab o (√x-1)² dx
1 Jawaban
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1. Jawaban Anonyme
InTegraL
∫(√x - 1)² dx [4...0]
= ∫(x - 2√x + 1) dx
= 1/2 x² - 2/(3/2) x^3/2 + x
= 1/2 x² - 4/3 x√x + x
= (4²/2 - 4/3 4√4 + 4) - 0
= 8 - 32/3 + 4
= 12 - 10 2/3
= 1 1/3