Volume kerucut yang tingginya 12 cm dan keliling alasnya 88 cm adalah

K = 2πr
88 = 2 × 22/7 × r
r = 88 × 7/44
r = 14 cm

V = 1/3πr²t
= 1/3×22/7×14×14×12
= 2×14×4
=112 cm³

k = 2 x phi x r
88 = 2 x 22/7 x r
88 = 44/7 x r
88 x7 = 44 xr
616 = 44 r
r = 616/44
r = 14 cm

V = 1/3 x phi x r^2 x t
V = 1/3 x 22/7 x 14 x14 x 12
V = 2464 cm3