Tentukan nilai x yang memenuhi persamaaan Berikut! 1. | 6x - 12 | = | x + 6 | 2. | 3x + 8 | = | 4 - 2x | 3. | 2x - 2 | = | x | Tolong di bantu ya kak, pr un

Persamaan Nilai Mutlak
|x| = √x²

1) |6x - 12| = |x + 6|
√(6x - 12)² = √(x + 6)²
√(36x² - 144x + 144) = √(x² + 12x + 36)
36x² - 144x + 144 = x² + 12x + 36
35x² - 156x + 108 = 0
(7x - 6)(5x - 18) = 0
x = 6/5 atau x = 18/5
HP = {6/5, 18/5} = {1 1/5, 3 3/5}

2) |3x + 8| = |4 - 2x|
√(3x + 8)² = √(4 - 2x)²
√(9x² + 48x + 64) = √(16 - 16x + 4x²)
9x² + 48x + 64 = 16 - 16x + 4x²
5x² + 64x + 48 = 0
(5x + 4)(x + 12) = 0
x = -4/5 atau x = -12
HP = {-12, -4/5}

3) |2x - 2| = |x|
√(2x - 2)² = √x²
√(4x² - 8x + 4) = √x²
4x² - 8x + 4 = x²
3x² - 8x + 4 = 0
(3x - 2)(x - 2) = 0
x = 2/3 atau x = 2
HP = {2/3, 2}