jika g(x) = x + 3 dan (f o g) (x) = x² - 4 maka f(x-2) =

[tex]g(x)=x+3 \\ (f\circ g)(x)=x^2-4 \\ (f\circ g)(x)=f(g(x)) \\ f(x+3)=x^2-4 \\ f((x+3)-5)=(x-5)^2-4 \\ f(x-2)=x^2-10x+25-4 \\ f(x-2)=x^2-10x+21[/tex]