Sebuah kawat baja (E = 2 . 10 pangkat 11 n/ m2) Pnjng 125 cm dan diameter 0,5 cm mengalami gaya tarik 1 n tentukan: A. Tegangan B. Regangan C. Pertambahan panja

Diket :
Kawat baja
Modulus, E = 2 x 10¹¹ N/m²
Panjang, L = 125 cm = 1,25 m
Dan diameter, d = 0,5 cm = 0,5 x 10¯² m
Gaya tarik, F = 1 N

Tanya :
Step 1
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Cari dulu luas penampang kawat, A = __?
Gunakan rumus :
A = π/4•d²
A = π/4•(0,5 x 10¯²)²
A = π/16•10^-4 m²

Step 2
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A] Tegangan
σ = F/A
σ = 1/(π/16•10^-4)
σ = (16/π) x 10^4 N/m²

B] Regangan, e = __?

E = σ/e
e = σ/E
e = (16/π) x 10^4 / (2 x 10¹¹)
e = (8/π) x 10^-7

C] pertambahan panjang, ΔL = __?
e = ΔL/L
ΔL = e.L
ΔL = (8/π) x 10^-7 • 1,25
ΔL = (10/π) x 10^-7 meter
ΔL = (1/π) x 10^-6 meter
ΔL = (1/π) µm

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FZA